Solve f(x)=-17/2x^3+1/8x^2-11x

$$f ( x ) = \frac { - 17 } { 2 x ^ { 3 } } + \frac { 1 } { 8 x ^ { 2 } } - 11 x$$

Evaluate

$$-11x+\frac{1}{8x^{2}}-\frac{17}{2x^{3}}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 2x^{3} and 8x^{2} is 8x^{3}. Multiply \frac{-17}{2x^{3}} times \frac{4}{4}. Multiply \frac{1}{8x^{2}} times \frac{x}{x}.

$$\frac{-17\times 4}{8x^{3}}+\frac{x}{8x^{3}}-11x$$

Since \frac{-17\times 4}{8x^{3}} and \frac{x}{8x^{3}} have the same denominator, add them by adding their numerators.

$$\frac{-17\times 4+x}{8x^{3}}-11x$$

Do the multiplications in -17\times 4+x.

$$\frac{-68+x}{8x^{3}}-11x$$

To add or subtract expressions, expand them to make their denominators the same. Multiply -11x times \frac{8x^{3}}{8x^{3}}.

$$\frac{-68+x}{8x^{3}}+\frac{-11x\times 8x^{3}}{8x^{3}}$$

Since \frac{-68+x}{8x^{3}} and \frac{-11x\times 8x^{3}}{8x^{3}} have the same denominator, add them by adding their numerators.

$$\frac{-68+x-11x\times 8x^{3}}{8x^{3}}$$

Do the multiplications in -68+x-11x\times 8x^{3}.

$$\frac{-68+x-88x^{4}}{8x^{3}}$$

Factor

$$\frac{-88x^{4}+x-68}{8x^{3}}$$