Solve f(t)=-4/t+8/t^2

$$f ( t ) = \frac { - 4 } { t } + \frac { 8 } { t ^ { 2 } }$$

Evaluate

$$-\frac{4\left(t-2\right)}{t^{2}}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of t and t^{2} is t^{2}. Multiply \frac{-4}{t} times \frac{t}{t}.

$$\frac{-4t}{t^{2}}+\frac{8}{t^{2}}$$

Since \frac{-4t}{t^{2}} and \frac{8}{t^{2}} have the same denominator, add them by adding their numerators.

$$\frac{-4t+8}{t^{2}}$$

Factor

$$-\frac{4\left(t-2\right)}{t^{2}}$$