Solve for c
c=\frac{3}{2f\cosh(x)}
f\neq 0
Solve for f
f=\frac{3}{2c\cosh(x)}
c\neq 0
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f\cosh(x)c=\frac{3}{2}
The equation is in standard form.
\frac{f\cosh(x)c}{f\cosh(x)}=\frac{\frac{3}{2}}{f\cosh(x)}
Divide both sides by f\cosh(x).
c=\frac{\frac{3}{2}}{f\cosh(x)}
Dividing by f\cosh(x) undoes the multiplication by f\cosh(x).
c=\frac{3}{2f\cosh(x)}
Divide \frac{3}{2} by f\cosh(x).
c\cosh(x)f=\frac{3}{2}
The equation is in standard form.
\frac{c\cosh(x)f}{c\cosh(x)}=\frac{\frac{3}{2}}{c\cosh(x)}
Divide both sides by c\cosh(x).
f=\frac{\frac{3}{2}}{c\cosh(x)}
Dividing by c\cosh(x) undoes the multiplication by c\cosh(x).
f=\frac{3}{2c\cosh(x)}
Divide \frac{3}{2} by c\cosh(x).
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