Solve f(3)=(1/20)(3)(0-12)(0-24)

$$f ( 3 ) = ( 1 / 20 ) ( 3 ) ( 0 - 12 ) ( 0 - 24 )$$

Evaluate

$$\frac{216}{5}=43.2$$

Solution Steps

Multiply \frac{1}{20} and 3 to get \frac{3}{20}.

$$\frac{3}{20}\left(0-12\right)\left(0-24\right)$$

Subtract 12 from 0 to get -12.

$$\frac{3}{20}\left(-12\right)\left(0-24\right)$$

Express \frac{3}{20}\left(-12\right) as a single fraction.

$$\frac{3\left(-12\right)}{20}\left(0-24\right)$$

Multiply 3 and -12 to get -36.

$$\frac{-36}{20}\left(0-24\right)$$

Reduce the fraction \frac{-36}{20} to lowest terms by extracting and canceling out 4.

$$-\frac{9}{5}\left(-24\right)$$

Express -\frac{9}{5}\left(-24\right) as a single fraction.

$$\frac{-9\left(-24\right)}{5}$$

Multiply -9 and -24 to get 216.

$$\frac{216}{5}$$

Factor

$$\frac{2 ^ {3} \cdot 3 ^ {3}}{5} = 43\frac{1}{5} = 43.2$$