Solve f(3)=(3)^3/3-(3)^2-3(3)

$$f ( 3 ) = \frac { ( 3 ) ^ { 3 } } { 3 } - ( 3 ) ^ { 2 } - 3 ( 3 )$$

Evaluate

$$-9$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 1 from 3 to get 2.

$$3^{2}-3^{2}-3\times 3$$

Calculate 3 to the power of 2 and get 9.

$$9-3^{2}-3\times 3$$

Calculate 3 to the power of 2 and get 9.

$$9-9-3\times 3$$

Subtract 9 from 9 to get 0.

$$0-3\times 3$$

Multiply 3 and 3 to get 9.

$$0-9$$

Subtract 9 from 0 to get -9.

$$-9$$

Factor

$$-9$$