Solve f(2m)=4(2m)^3-3(2m)^2+2(2m)-1

$$f ( 2 m ) = 4 ( 2 m ) ^ { 3 } - 3 ( 2 m ) ^ { 2 } + 2 ( 2 m ) - 1$$

Evaluate

$$32m^{3}-12m^{2}+4m-1$$

Solution Steps

Expand \left(2m\right)^{3}.

$$4\times 2^{3}m^{3}-3\times \left(2m\right)^{2}+2\times 2m-1$$

Calculate 2 to the power of 3 and get 8.

$$4\times 8m^{3}-3\times \left(2m\right)^{2}+2\times 2m-1$$

Multiply 4 and 8 to get 32.

$$32m^{3}-3\times \left(2m\right)^{2}+2\times 2m-1$$

Expand \left(2m\right)^{2}.

$$32m^{3}-3\times 2^{2}m^{2}+2\times 2m-1$$

Calculate 2 to the power of 2 and get 4.

$$32m^{3}-3\times 4m^{2}+2\times 2m-1$$

Multiply 3 and 4 to get 12.

$$32m^{3}-12m^{2}+2\times 2m-1$$

Multiply 2 and 2 to get 4.

$$32m^{3}-12m^{2}+4m-1$$

Expand

$$32m^{3}-12m^{2}+4m-1$$

Solution Steps

Expand \left(2m\right)^{3}.

$$4\times 2^{3}m^{3}-3\times \left(2m\right)^{2}+2\times 2m-1$$

Calculate 2 to the power of 3 and get 8.

$$4\times 8m^{3}-3\times \left(2m\right)^{2}+2\times 2m-1$$

Multiply 4 and 8 to get 32.

$$32m^{3}-3\times \left(2m\right)^{2}+2\times 2m-1$$

Expand \left(2m\right)^{2}.

$$32m^{3}-3\times 2^{2}m^{2}+2\times 2m-1$$

Calculate 2 to the power of 2 and get 4.

$$32m^{3}-3\times 4m^{2}+2\times 2m-1$$

Multiply 3 and 4 to get 12.

$$32m^{3}-12m^{2}+2\times 2m-1$$

Multiply 2 and 2 to get 4.

$$32m^{3}-12m^{2}+4m-1$$