Solve f(11/2)=(11/2)-1/2(1frac{1{2})^2-(11/2)^2}=

$$f ( 1 \frac { 1 } { 2 } ) = \frac { ( 1 \frac { 1 } { 2 } ) - 1 } { 2 ( 1 \frac { 1 } { 2 } ) ^ { 2 } - ( 1 \frac { 1 } { 2 } ) ^ { 2 } } =$$

Evaluate

$$\frac{2}{9}\approx 0.222222222$$

Solution Steps

Multiply 1 and 2 to get 2.

$$\frac{\frac{2+1}{2}-1}{2\times \left(\frac{1\times 2+1}{2}\right)^{2}-\left(\frac{1\times 2+1}{2}\right)^{2}}$$

Add 2 and 1 to get 3.

$$\frac{\frac{3}{2}-1}{2\times \left(\frac{1\times 2+1}{2}\right)^{2}-\left(\frac{1\times 2+1}{2}\right)^{2}}$$

Subtract 1 from \frac{3}{2} to get \frac{1}{2}.

$$\frac{\frac{1}{2}}{2\times \left(\frac{1\times 2+1}{2}\right)^{2}-\left(\frac{1\times 2+1}{2}\right)^{2}}$$

Multiply 1 and 2 to get 2.

$$\frac{\frac{1}{2}}{2\times \left(\frac{2+1}{2}\right)^{2}-\left(\frac{1\times 2+1}{2}\right)^{2}}$$

Add 2 and 1 to get 3.

$$\frac{\frac{1}{2}}{2\times \left(\frac{3}{2}\right)^{2}-\left(\frac{1\times 2+1}{2}\right)^{2}}$$

Calculate \frac{3}{2} to the power of 2 and get \frac{9}{4}.

$$\frac{\frac{1}{2}}{2\times \frac{9}{4}-\left(\frac{1\times 2+1}{2}\right)^{2}}$$

Multiply 2 and \frac{9}{4} to get \frac{9}{2}.

$$\frac{\frac{1}{2}}{\frac{9}{2}-\left(\frac{1\times 2+1}{2}\right)^{2}}$$

Multiply 1 and 2 to get 2.

$$\frac{\frac{1}{2}}{\frac{9}{2}-\left(\frac{2+1}{2}\right)^{2}}$$

Add 2 and 1 to get 3.

$$\frac{\frac{1}{2}}{\frac{9}{2}-\left(\frac{3}{2}\right)^{2}}$$

Calculate \frac{3}{2} to the power of 2 and get \frac{9}{4}.

$$\frac{\frac{1}{2}}{\frac{9}{2}-\frac{9}{4}}$$

Subtract \frac{9}{4} from \frac{9}{2} to get \frac{9}{4}.

$$\frac{\frac{1}{2}}{\frac{9}{4}}$$

Divide \frac{1}{2} by \frac{9}{4} by multiplying \frac{1}{2} by the reciprocal of \frac{9}{4}.

$$\frac{1}{2}\times \frac{4}{9}$$

Multiply \frac{1}{2} and \frac{4}{9} to get \frac{2}{9}.

$$\frac{2}{9}$$

Factor

$$\frac{2}{3 ^ {2}} = 0.2222222222222222$$