Solve f(1+r)=1/(1+r-1)^2=1/r^2text{et}f(1-r)=1/(1-r-1)

$$f ( 1 + r ) = \frac { 1 } { ( 1 + r - 1 ) ^ { 2 } } = \frac { 1 } { r ^ { 2 } } \text { et } f ( 1 - r ) = \frac { 1 } { ( 1 - r - 1 ) }$$

Solve for r

$$r\neq 0$$

Solution Steps

Variable r cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by r^{2}, the least common multiple of \left(1+r-1\right)^{2},r^{2}.

$$1=1$$

This is true for any r.

$$r\in \mathrm{R}$$

Variable r cannot be equal to 0.

$$r\in \mathrm{R}\setminus 0$$