Solve f(-6)=-6^2+3(-6)/-6^2-6

$$f ( - 6 ) = \frac { - 6 ^ { 2 } + 3 ( - 6 ) } { - 6 ^ { 2 } - 6 }$$

Evaluate

$$\frac{9}{7}\approx 1.285714286$$

Solution Steps

Calculate 6 to the power of 2 and get 36.

$$\frac{-36+3\left(-6\right)}{-6^{2}-6}$$

Multiply 3 and -6 to get -18.

$$\frac{-36-18}{-6^{2}-6}$$

Subtract 18 from -36 to get -54.

$$\frac{-54}{-6^{2}-6}$$

Calculate 6 to the power of 2 and get 36.

$$\frac{-54}{-36-6}$$

Subtract 6 from -36 to get -42.

$$\frac{-54}{-42}$$

Reduce the fraction \frac{-54}{-42} to lowest terms by extracting and canceling out -6.

$$\frac{9}{7}$$

Factor

$$\frac{3 ^ {2}}{7} = 1\frac{2}{7} = 1.2857142857142858$$