Solve f(-3)=(-3)^3-2(-3)^2/(-3)^2-4

$$f ( - 3 ) = \frac { ( - 3 ) ^ { 3 } - 2 ( - 3 ) ^ { 2 } } { ( - 3 ) ^ { 2 } - 4 }$$

Evaluate

$$-9$$

Solution Steps

Calculate -3 to the power of 3 and get -27.

$$\frac{-27-2\left(-3\right)^{2}}{\left(-3\right)^{2}-4}$$

Calculate -3 to the power of 2 and get 9.

$$\frac{-27-2\times 9}{\left(-3\right)^{2}-4}$$

Multiply 2 and 9 to get 18.

$$\frac{-27-18}{\left(-3\right)^{2}-4}$$

Subtract 18 from -27 to get -45.

$$\frac{-45}{\left(-3\right)^{2}-4}$$

Calculate -3 to the power of 2 and get 9.

$$\frac{-45}{9-4}$$

Subtract 4 from 9 to get 5.

$$\frac{-45}{5}$$

Divide -45 by 5 to get -9.

$$-9$$

Factor

$$-9$$