Skip to main content
Solve for f
Tick mark Image
Solve for a (complex solution)
Tick mark Image

Similar Problems from Web Search

Share

f\left(a+1\right)\left(a+1\right)+ga\left(a-1\right)=3a\left(a+1\right)
Multiply both sides of the equation by a\left(a+1\right), the least common multiple of a,a+1.
f\left(a+1\right)^{2}+ga\left(a-1\right)=3a\left(a+1\right)
Multiply a+1 and a+1 to get \left(a+1\right)^{2}.
f\left(a^{2}+2a+1\right)+ga\left(a-1\right)=3a\left(a+1\right)
Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(a+1\right)^{2}.
fa^{2}+2fa+f+ga\left(a-1\right)=3a\left(a+1\right)
Use the distributive property to multiply f by a^{2}+2a+1.
fa^{2}+2fa+f+ga^{2}-ga=3a\left(a+1\right)
Use the distributive property to multiply ga by a-1.
fa^{2}+2fa+f+ga^{2}-ga=3a^{2}+3a
Use the distributive property to multiply 3a by a+1.
fa^{2}+2fa+f-ga=3a^{2}+3a-ga^{2}
Subtract ga^{2} from both sides.
fa^{2}+2fa+f=3a^{2}+3a-ga^{2}+ga
Add ga to both sides.
2af+fa^{2}+f=3a^{2}+ag+3a-ga^{2}
Reorder the terms.
\left(2a+a^{2}+1\right)f=3a^{2}+ag+3a-ga^{2}
Combine all terms containing f.
\left(a^{2}+2a+1\right)f=3a^{2}+ag+3a-ga^{2}
The equation is in standard form.
\frac{\left(a^{2}+2a+1\right)f}{a^{2}+2a+1}=\frac{a\left(3+g+3a-ag\right)}{a^{2}+2a+1}
Divide both sides by a^{2}+2a+1.
f=\frac{a\left(3+g+3a-ag\right)}{a^{2}+2a+1}
Dividing by a^{2}+2a+1 undoes the multiplication by a^{2}+2a+1.
f=\frac{a\left(3+g+3a-ag\right)}{\left(a+1\right)^{2}}
Divide a\left(3a+g+3-ga\right) by a^{2}+2a+1.