Solve ftan^-12x+tan^-13x=pi/4

$$f \tan ^ { - 1 } 2 x + \tan ^ { - 1 } 3 x = \frac { \pi } { 4 }$$

Solve for f

$$f=-\frac{4\arctan(3x)-\pi }{4\arctan(2x)}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 4.

$$4f\arctan(2x)+4\arctan(3x)=\pi$$

Subtract 4\arctan(3x) from both sides.

$$4f\arctan(2x)=\pi -4\arctan(3x)$$

The equation is in standard form.

$$4\arctan(2x)f=-4\arctan(3x)+\pi$$

Divide both sides by 4\arctan(2x).

$$\frac{4\arctan(2x)f}{4\arctan(2x)}=\frac{-4\arctan(3x)+\pi }{4\arctan(2x)}$$

Dividing by 4\arctan(2x) undoes the multiplication by 4\arctan(2x).

$$f=\frac{-4\arctan(3x)+\pi }{4\arctan(2x)}$$