Solve fx+a/x-b=2

$$f \frac { x + a } { x - b } = 2$$

Solve for a

$$a=-\frac{fx-2x+2b}{f}$$

$$x\neq b\text{ and }f\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by x-b.

$$f\left(x+a\right)=2\left(x-b\right)$$

Use the distributive property to multiply f by x+a.

$$fx+fa=2\left(x-b\right)$$

Use the distributive property to multiply 2 by x-b.

$$fx+fa=2x-2b$$

Subtract fx from both sides.

$$fa=2x-2b-fx$$

The equation is in standard form.

$$fa=-fx+2x-2b$$

Divide both sides by f.

$$\frac{fa}{f}=\frac{-fx+2x-2b}{f}$$

Dividing by f undoes the multiplication by f.

$$a=\frac{-fx+2x-2b}{f}$$

Solve for b

$$b=-\frac{af}{2}-\frac{fx}{2}+x$$

$$x\neq -a\text{ and }f\neq 0$$