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f\frac{\mathrm{d}(y)}{\mathrm{d}x^{2}}=0+\frac{\mathrm{d}(y)}{\mathrm{d}x}
Add \frac{\mathrm{d}(y)}{\mathrm{d}x} to both sides.
f\frac{\mathrm{d}(y)}{\mathrm{d}x^{2}}=\frac{\mathrm{d}(y)}{\mathrm{d}x}
Anything plus zero gives itself.
\text{true}
The equation is in standard form.
f\in \mathrm{R}
This is true for any f.