Solve for f
f=\frac{5}{2x}
x\neq 0
Solve for x
x=\frac{5}{2f}
f\neq 0
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\frac{5x}{2}f=\frac{25}{4}
The equation is in standard form.
\frac{2\times \frac{5x}{2}f}{5x}=\frac{2\times \frac{25}{4}}{5x}
Divide both sides by \frac{5}{2}x.
f=\frac{2\times \frac{25}{4}}{5x}
Dividing by \frac{5}{2}x undoes the multiplication by \frac{5}{2}x.
f=\frac{5}{2x}
Divide \frac{25}{4} by \frac{5}{2}x.
\frac{5f}{2}x=\frac{25}{4}
The equation is in standard form.
\frac{2\times \frac{5f}{2}x}{5f}=\frac{2\times \frac{25}{4}}{5f}
Divide both sides by \frac{5}{2}f.
x=\frac{2\times \frac{25}{4}}{5f}
Dividing by \frac{5}{2}f undoes the multiplication by \frac{5}{2}f.
x=\frac{5}{2f}
Divide \frac{25}{4} by \frac{5}{2}f.
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