Solve f3/7+x=17/7

$$f \frac { 3 } { 7 } + x = \frac { 17 } { 7 }$$

Solve for f

$$f=\frac{17-7x}{3}$$

Steps for Solving Linear Equation

Subtract x from both sides.

$$f\times \frac{3}{7}=\frac{17}{7}-x$$

The equation is in standard form.

$$\frac{3}{7}f=\frac{17}{7}-x$$

Divide both sides of the equation by \frac{3}{7}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{3}{7}f}{\frac{3}{7}}=\frac{\frac{17}{7}-x}{\frac{3}{7}}$$

Dividing by \frac{3}{7} undoes the multiplication by \frac{3}{7}.

$$f=\frac{\frac{17}{7}-x}{\frac{3}{7}}$$

Divide \frac{17}{7}-x by \frac{3}{7} by multiplying \frac{17}{7}-x by the reciprocal of \frac{3}{7}.

$$f=\frac{17-7x}{3}$$

Solve for x

$$x=\frac{17-3f}{7}$$

Solution Steps

Subtract f\times \frac{3}{7} from both sides.

$$x=\frac{17}{7}-f\times \frac{3}{7}$$

Multiply -1 and \frac{3}{7} to get -\frac{3}{7}.

$$x=\frac{17}{7}-\frac{3}{7}f$$