Solve f^2=16=

$$f ^ { 2 } = 16 =$$

Solve for f

$$f=4$$

$$f=-4$$

Steps Using Difference of Squares

Subtract 16 from both sides.

$$f^{2}-16=0$$

Consider f^{2}-16. Rewrite f^{2}-16 as f^{2}-4^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(f-4\right)\left(f+4\right)=0$$

To find equation solutions, solve f-4=0 and f+4=0.

$$f=4 f=-4$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$f=4 f=-4$$

Steps Using the Quadratic Formula

Subtract 16 from both sides.

$$f^{2}-16=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -16 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$f=\frac{0±\sqrt{0^{2}-4\left(-16\right)}}{2}$$

Square 0.

$$f=\frac{0±\sqrt{-4\left(-16\right)}}{2}$$

Multiply -4 times -16.

$$f=\frac{0±\sqrt{64}}{2}$$

Take the square root of 64.

$$f=\frac{0±8}{2}$$

Now solve the equation f=\frac{0±8}{2} when ± is plus. Divide 8 by 2.

$$f=4$$

Now solve the equation f=\frac{0±8}{2} when ± is minus. Divide -8 by 2.

$$f=-4$$

The equation is now solved.

$$f=4 f=-4$$