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f\left(f+19\right)=0
Factor out f.
f=0 f=-19
To find equation solutions, solve f=0 and f+19=0.
f^{2}+19f=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
f=\frac{-19±\sqrt{19^{2}}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 19 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
f=\frac{-19±19}{2}
Take the square root of 19^{2}.
f=\frac{0}{2}
Now solve the equation f=\frac{-19±19}{2} when ± is plus. Add -19 to 19.
f=0
Divide 0 by 2.
f=-\frac{38}{2}
Now solve the equation f=\frac{-19±19}{2} when ± is minus. Subtract 19 from -19.
f=-19
Divide -38 by 2.
f=0 f=-19
The equation is now solved.
f^{2}+19f=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
f^{2}+19f+\left(\frac{19}{2}\right)^{2}=\left(\frac{19}{2}\right)^{2}
Divide 19, the coefficient of the x term, by 2 to get \frac{19}{2}. Then add the square of \frac{19}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
f^{2}+19f+\frac{361}{4}=\frac{361}{4}
Square \frac{19}{2} by squaring both the numerator and the denominator of the fraction.
\left(f+\frac{19}{2}\right)^{2}=\frac{361}{4}
Factor f^{2}+19f+\frac{361}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(f+\frac{19}{2}\right)^{2}}=\sqrt{\frac{361}{4}}
Take the square root of both sides of the equation.
f+\frac{19}{2}=\frac{19}{2} f+\frac{19}{2}=-\frac{19}{2}
Simplify.
f=0 f=-19
Subtract \frac{19}{2} from both sides of the equation.