Solve f^-1(10)=-2(10)+17/10-9=

$$f ^ { - 1 } ( 10 ) = \frac { - 2 ( 10 ) + 17 } { 10 - 9 } =$$

Solve for f

$$f = -\frac{10}{3} = -3\frac{1}{3} \approx -3.333333333$$

Steps for Solving Linear Equation

Multiply -2 and 10 to get -20.

$$f^{-1}\times 10=\frac{-20+17}{10-9}$$

Add -20 and 17 to get -3.

$$f^{-1}\times 10=\frac{-3}{10-9}$$

Subtract 9 from 10 to get 1.

$$f^{-1}\times 10=\frac{-3}{1}$$

Anything divided by one gives itself.

$$f^{-1}\times 10=-3$$

Divide both sides by 10.

$$f^{-1}=-\frac{3}{10}$$

Reorder the terms.

$$\frac{1}{f}=-\frac{3}{10}$$

Variable f cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 10f, the least common multiple of f,10.

$$10=-3f$$

Swap sides so that all variable terms are on the left hand side.

$$-3f=10$$

Divide both sides by -3.

$$f=\frac{10}{-3}$$

Fraction \frac{10}{-3} can be rewritten as -\frac{10}{3} by extracting the negative sign.

$$f=-\frac{10}{3}$$