Solve for f
f=-y\left(3x^{2}-2x+3\right)
y\neq 0
Solve for x (complex solution)
x=\frac{-\sqrt{y\left(-8y-3f\right)}+y}{3y}
x=\frac{\sqrt{-y\left(8y+3f\right)}+y}{3y}\text{, }y\neq 0
Solve for x
x=\frac{-\sqrt{y\left(-8y-3f\right)}+y}{3y}
x=\frac{\sqrt{-y\left(8y+3f\right)}+y}{3y}\text{, }\left(y>0\text{ and }f\leq -\frac{8y}{3}\right)\text{ or }\left(f\geq -\frac{8y}{3}\text{ and }y<0\right)\text{ or }\left(y\neq 0\text{ and }f=-\frac{8y}{3}\right)
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\frac{1}{y}f=-3x^{2}+2x-3
The equation is in standard form.
\frac{\frac{1}{y}fy}{1}=\frac{\left(-3x^{2}+2x-3\right)y}{1}
Divide both sides by y^{-1}.
f=\frac{\left(-3x^{2}+2x-3\right)y}{1}
Dividing by y^{-1} undoes the multiplication by y^{-1}.
f=y\left(-3x^{2}+2x-3\right)
Divide -3x^{2}+2x-3 by y^{-1}.
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