Solve for f (complex solution)
f=y\sqrt{\left(2-x\right)\left(x+5\right)}
y\neq 0
Solve for f
f=y\sqrt{\left(2-x\right)\left(x+5\right)}
y\neq 0\text{ and }x\geq -5\text{ and }x\leq 2
Solve for x (complex solution)
x=-\frac{\sqrt{49y^{4}-4\left(fy\right)^{2}}}{2y^{2}}-\frac{3}{2}
x=\frac{\sqrt{49y^{4}-4\left(fy\right)^{2}}}{2y^{2}}-\frac{3}{2}\text{, }y\neq 0\text{ and }\left(|arg(\sqrt{\left(\frac{f}{y}\right)^{2}}y)-arg(f)|<\pi \text{ or }f=0\right)
Solve for x
x=-\frac{\sqrt{49y^{2}-4f^{2}}}{2y}-\frac{3}{2}
x=\frac{\sqrt{49y^{2}-4f^{2}}}{2y}-\frac{3}{2}\text{, }f\neq -\frac{7y}{2}\text{ and }y\neq 0\text{ and }f\leq \frac{7|y|}{2}\text{ and }f\geq -\frac{7|y|}{2}\text{ and }\left(f\geq \frac{7y}{2}\text{ or }f\geq 0\right)\text{ and }\left(f\leq 0\text{ or }f\leq \frac{7y}{2}\right)
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\frac{1}{y}f=\sqrt{10-3x-x^{2}}
The equation is in standard form.
\frac{\frac{1}{y}fy}{1}=\frac{\sqrt{\left(2-x\right)\left(x+5\right)}y}{1}
Divide both sides by y^{-1}.
f=\frac{\sqrt{\left(2-x\right)\left(x+5\right)}y}{1}
Dividing by y^{-1} undoes the multiplication by y^{-1}.
f=y\sqrt{\left(2-x\right)\left(x+5\right)}
Divide \sqrt{\left(2-x\right)\left(5+x\right)} by y^{-1}.
\frac{1}{y}f=\sqrt{10-3x-x^{2}}
The equation is in standard form.
\frac{\frac{1}{y}fy}{1}=\frac{\sqrt{\left(2-x\right)\left(x+5\right)}y}{1}
Divide both sides by y^{-1}.
f=\frac{\sqrt{\left(2-x\right)\left(x+5\right)}y}{1}
Dividing by y^{-1} undoes the multiplication by y^{-1}.
f=y\sqrt{\left(2-x\right)\left(x+5\right)}
Divide \sqrt{\left(2-x\right)\left(5+x\right)} by y^{-1}.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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