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e^{p+3}-6=5
Use the rules of exponents and logarithms to solve the equation.
e^{p+3}=11
Add 6 to both sides of the equation.
\log(e^{p+3})=\log(11)
Take the logarithm of both sides of the equation.
\left(p+3\right)\log(e)=\log(11)
The logarithm of a number raised to a power is the power times the logarithm of the number.
p+3=\frac{\log(11)}{\log(e)}
Divide both sides by \log(e).
p+3=\log_{e}\left(11\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
p=\ln(11)-3
Subtract 3 from both sides of the equation.