Solve e^it^2dx=1

$$e ^ { i t ^ { 2 } } d x = 1$$

Solve for d

$$d=\frac{e^{-it^{2}}}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

The equation is in standard form.

$$xe^{it^{2}}d=1$$

Divide both sides by e^{it^{2}}x.

$$\frac{xe^{it^{2}}d}{xe^{it^{2}}}=\frac{1}{xe^{it^{2}}}$$

Dividing by e^{it^{2}}x undoes the multiplication by e^{it^{2}}x.

$$d=\frac{1}{xe^{it^{2}}}$$

Divide 1 by e^{it^{2}}x.

$$d=\frac{e^{-it^{2}}}{x}$$

Solve for t

$$t=-\sqrt{-i\ln(\frac{1}{dx})+2\pi n_{1}}\text{, }n_{1}\in \mathrm{Z}$$

$$t=\sqrt{-i\ln(\frac{1}{dx})+2\pi n_{1}}\text{, }n_{1}\in \mathrm{Z}\text{, }dx\neq 0$$