Solve for x
x=-\frac{10+e^{b^{2}}-b}{b}
b\neq 0
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e^{b^{2}}+bx=b-10
Multiply b and b to get b^{2}.
bx=b-10-e^{b^{2}}
Subtract e^{b^{2}} from both sides.
bx=-e^{b^{2}}+b-10
Reorder the terms.
bx=b-e^{b^{2}}-10
The equation is in standard form.
\frac{bx}{b}=\frac{b-e^{b^{2}}-10}{b}
Divide both sides by b.
x=\frac{b-e^{b^{2}}-10}{b}
Dividing by b undoes the multiplication by b.
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