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e^{99x}=4879
Use the rules of exponents and logarithms to solve the equation.
\log(e^{99x})=\log(4879)
Take the logarithm of both sides of the equation.
99x\log(e)=\log(4879)
The logarithm of a number raised to a power is the power times the logarithm of the number.
99x=\frac{\log(4879)}{\log(e)}
Divide both sides by \log(e).
99x=\log_{e}\left(4879\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
x=\frac{\ln(4879)}{99}
Divide both sides by 99.