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e^{4x-8}=16
Use the rules of exponents and logarithms to solve the equation.
\log(e^{4x-8})=\log(16)
Take the logarithm of both sides of the equation.
\left(4x-8\right)\log(e)=\log(16)
The logarithm of a number raised to a power is the power times the logarithm of the number.
4x-8=\frac{\log(16)}{\log(e)}
Divide both sides by \log(e).
4x-8=\log_{e}\left(16\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
4x=4\ln(2)-\left(-8\right)
Add 8 to both sides of the equation.
x=\frac{4\ln(2)+8}{4}
Divide both sides by 4.