Solve e:(7/6-3/4)*4/5

$$e : ( \frac { 7 } { 6 } - \frac { 3 } { 4 } ) \cdot \frac { 4 } { 5 }$$

Evaluate

$$\frac{48e}{25}\approx 5.219101111$$

Solution Steps

Least common multiple of 6 and 4 is 12. Convert \frac{7}{6} and \frac{3}{4} to fractions with denominator 12.

$$\frac{e}{\frac{14}{12}-\frac{9}{12}}\times \frac{4}{5}$$

Since \frac{14}{12} and \frac{9}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{e}{\frac{14-9}{12}}\times \frac{4}{5}$$

Subtract 9 from 14 to get 5.

$$\frac{e}{\frac{5}{12}}\times \frac{4}{5}$$

Divide e by \frac{5}{12} by multiplying e by the reciprocal of \frac{5}{12}.

$$\frac{e\times 12}{5}\times \frac{4}{5}$$

Multiply \frac{e\times 12}{5} times \frac{4}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{e\times 12\times 4}{5\times 5}$$

Multiply 12 and 4 to get 48.

$$\frac{e\times 48}{5\times 5}$$

Multiply 5 and 5 to get 25.

$$\frac{e\times 48}{25}$$