Solve dx+3=dy

$$d x + 3 = d y$$

Solve for d

$$d=-\frac{3}{x-y}$$

$$x\neq y$$

Steps for Solving Linear Equation

Subtract dy from both sides.

$$dx+3-dy=0$$

Subtract 3 from both sides. Anything subtracted from zero gives its negation.

$$dx-dy=-3$$

Combine all terms containing d.

$$\left(x-y\right)d=-3$$

Divide both sides by x-y.

$$\frac{\left(x-y\right)d}{x-y}=-\frac{3}{x-y}$$

Dividing by x-y undoes the multiplication by x-y.

$$d=-\frac{3}{x-y}$$

Solve for x

$$x=y-\frac{3}{d}$$

$$d\neq 0$$

Steps for Solving Linear Equation

Subtract 3 from both sides.

$$dx=dy-3$$

Divide both sides by d.

$$\frac{dx}{d}=\frac{dy-3}{d}$$

Dividing by d undoes the multiplication by d.

$$x=\frac{dy-3}{d}$$

Divide dy-3 by d.

$$x=y-\frac{3}{d}$$