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Solve for d
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d^{2}=2
Multiply d and d to get d^{2}.
d=\sqrt{2} d=-\sqrt{2}
Take the square root of both sides of the equation.
d^{2}=2
Multiply d and d to get d^{2}.
d^{2}-2=0
Subtract 2 from both sides.
d=\frac{0±\sqrt{0^{2}-4\left(-2\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -2 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
d=\frac{0±\sqrt{-4\left(-2\right)}}{2}
Square 0.
d=\frac{0±\sqrt{8}}{2}
Multiply -4 times -2.
d=\frac{0±2\sqrt{2}}{2}
Take the square root of 8.
d=\sqrt{2}
Now solve the equation d=\frac{0±2\sqrt{2}}{2} when ± is plus.
d=-\sqrt{2}
Now solve the equation d=\frac{0±2\sqrt{2}}{2} when ± is minus.
d=\sqrt{2} d=-\sqrt{2}
The equation is now solved.