Solve d110^x-2x+2=100

$$d 110 ^ { x - 2 x + 2 } = 100$$

Solve for d

$$d=\frac{110^{x}}{121}$$

Steps for Solving Linear Equation

Combine x and -2x to get -x.

$$d\times 110^{-x+2}=100$$

The equation is in standard form.

$$110^{2-x}d=100$$

Divide both sides by 110^{-x+2}.

$$\frac{110^{2-x}d}{110^{2-x}}=\frac{100}{110^{2-x}}$$

Dividing by 110^{-x+2} undoes the multiplication by 110^{-x+2}.

$$d=\frac{100}{110^{2-x}}$$

Divide 100 by 110^{-x+2}.

$$d=\frac{110^{x}}{121}$$

Solve for x (complex solution)

$$x=\frac{\ln(d)+2\ln(11)}{\ln(110)}-\frac{2\pi n_{1}i}{\ln(110)}$$

$$n_{1}\in \mathrm{Z}$$

$$d\neq 0$$

Solve for x

$$x=\frac{\ln(d)+2\ln(11)}{\ln(110)}$$

$$d>0$$