Solve d(1,41*10^-3)=(0,25+d)(1*10^-5)

$$d ( 1,41 \times 10 ^ { - 3 } ) = ( 0,25 + d ) ( 1 \times 10 ^ { - 5 } )$$

Solve for d

$$d=\frac{1}{560}\approx 0,001785714$$

Steps for Solving Linear Equation

Calculate 10 to the power of -3 and get \frac{1}{1000}.

$$d\left(1,41\times \left(\frac{1}{1000}\right)\right)=\left(0,25+d\right)\left(1\times 10^{-5}\right)$$

Calculate 10 to the power of -5 and get \frac{1}{100000}.

$$d\left(1,41\times \left(\frac{1}{1000}\right)\right)=\left(0,25+d\right)\left(1\times \left(\frac{1}{100000}\right)\right)$$

Use the distributive property to multiply 0,25+d by 1\times \left(\frac{1}{100000}\right).

$$d\left(1,41\times \left(\frac{1}{1000}\right)\right)=0,25\left(1\times \left(\frac{1}{100000}\right)\right)+d\left(1\times \left(\frac{1}{100000}\right)\right)$$

Subtract d\left(1\times \left(\frac{1}{100000}\right)\right) from both sides.

$$d\left(1,41\times \left(\frac{1}{1000}\right)\right)-d\left(1\times \left(\frac{1}{100000}\right)\right)=0,25\left(1\times \left(\frac{1}{100000}\right)\right)$$

Combine all terms containing d.

$$\left(1,41\times \left(\frac{1}{1000}\right)-1\times \left(\frac{1}{100000}\right)\right)d=0,25\left(1\times \left(\frac{1}{100000}\right)\right)$$

The equation is in standard form.

$$\frac{7}{5000}d=\frac{1}{400000}$$

Divide both sides of the equation by \frac{7}{5000}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{7}{5000}d}{\frac{7}{5000}}=\frac{\frac{1}{400000}}{\frac{7}{5000}}$$

Dividing by \frac{7}{5000} undoes the multiplication by \frac{7}{5000}.

$$d=\frac{\frac{1}{400000}}{\frac{7}{5000}}$$

Divide \frac{1}{400000} by \frac{7}{5000} by multiplying \frac{1}{400000} by the reciprocal of \frac{7}{5000}.

$$d=\frac{1}{560}$$