Solve d^2X+bX=0

$$d ^ { 2 } X + b X = 0$$

Solve for X

$$\left\{\begin{matrix}\\X=0\text{, }&\text{unconditionally}\\X\in \mathrm{R}\text{, }&b=-d^{2}\end{matrix}\right.$$

Steps for Solving Linear Equation

Combine all terms containing X.

$$\left(d^{2}+b\right)X=0$$

The equation is in standard form.

$$\left(b+d^{2}\right)X=0$$

Divide 0 by d^{2}+b.

$$X=0$$

Solve for b

$$\left\{\begin{matrix}\\b=-d^{2}\text{, }&\text{unconditionally}\\b\in \mathrm{R}\text{, }&X=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract d^{2}X from both sides. Anything subtracted from zero gives its negation.

$$bX=-d^{2}X$$

Reorder the terms.

$$Xb=-Xd^{2}$$

Divide both sides by X.

$$\frac{Xb}{X}=-\frac{Xd^{2}}{X}$$

Dividing by X undoes the multiplication by X.

$$b=-\frac{Xd^{2}}{X}$$

Divide -Xd^{2} by X.

$$b=-d^{2}$$