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Solve for d
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d^{2}=50
Add 50 to both sides. Anything plus zero gives itself.
d=5\sqrt{2} d=-5\sqrt{2}
Take the square root of both sides of the equation.
d^{2}-50=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
d=\frac{0±\sqrt{0^{2}-4\left(-50\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -50 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
d=\frac{0±\sqrt{-4\left(-50\right)}}{2}
Square 0.
d=\frac{0±\sqrt{200}}{2}
Multiply -4 times -50.
d=\frac{0±10\sqrt{2}}{2}
Take the square root of 200.
d=5\sqrt{2}
Now solve the equation d=\frac{0±10\sqrt{2}}{2} when ± is plus.
d=-5\sqrt{2}
Now solve the equation d=\frac{0±10\sqrt{2}}{2} when ± is minus.
d=5\sqrt{2} d=-5\sqrt{2}
The equation is now solved.