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d=\sqrt{3^{2}+3}
Subtract 4 from 7 to get 3.
d=\sqrt{9+3}
Calculate 3 to the power of 2 and get 9.
d=\sqrt{12}
Add 9 and 3 to get 12.
d=2\sqrt{3}
Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.