Solve d=sqrt{(3-(-1))^2+(4-(-2))^2}

$$d = \sqrt { ( 3 - ( - 1 ) ) ^ { 2 } + ( 4 - ( - 2 ) ) ^ { 2 } }$$

Solve for d

$$d=2\sqrt{13}\approx 7.211102551$$

Steps for Solving Linear Equation

The opposite of -1 is 1.

$$d=\sqrt{\left(3+1\right)^{2}+\left(4-\left(-2\right)\right)^{2}}$$

Add 3 and 1 to get 4.

$$d=\sqrt{4^{2}+\left(4-\left(-2\right)\right)^{2}}$$

Calculate 4 to the power of 2 and get 16.

$$d=\sqrt{16+\left(4-\left(-2\right)\right)^{2}}$$

The opposite of -2 is 2.

$$d=\sqrt{16+\left(4+2\right)^{2}}$$

Add 4 and 2 to get 6.

$$d=\sqrt{16+6^{2}}$$

Calculate 6 to the power of 2 and get 36.

$$d=\sqrt{16+36}$$

Add 16 and 36 to get 52.

$$d=\sqrt{52}$$

Factor 52=2^{2}\times 13. Rewrite the square root of the product \sqrt{2^{2}\times 13} as the product of square roots \sqrt{2^{2}}\sqrt{13}. Take the square root of 2^{2}.

$$d=2\sqrt{13}$$

Assign d

$$d≔2\sqrt{13}$$