Solve d=frac{|1-sqrt{3}*sqrt{3}-2|}{sqrt{1^2+3}}

$$d = \frac { | 1 - \sqrt { 3 } \cdot \sqrt { 3 } - 2 | } { \sqrt { 1 ^ { 2 } + 3 } }$$

Solve for d

$$d=2$$

Steps for Solving Linear Equation

Multiply \sqrt{3} and \sqrt{3} to get 3.

$$d=\frac{|1-3-2|}{\sqrt{1^{2}+3}}$$

Subtract 3 from 1 to get -2.

$$d=\frac{|-2-2|}{\sqrt{1^{2}+3}}$$

Subtract 2 from -2 to get -4.

$$d=\frac{|-4|}{\sqrt{1^{2}+3}}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -4 is 4.

$$d=\frac{4}{\sqrt{1^{2}+3}}$$

Calculate 1 to the power of 2 and get 1.

$$d=\frac{4}{\sqrt{1+3}}$$

Add 1 and 3 to get 4.

$$d=\frac{4}{\sqrt{4}}$$

Calculate the square root of 4 and get 2.

$$d=\frac{4}{2}$$

Divide 4 by 2 to get 2.

$$d=2$$

Assign d

$$d≔2$$