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\left(-c_{1}+c_{3}^{5}\right)\left(c_{1}^{2}+c_{1}c_{3}^{5}+c_{3}^{10}\right)
Rewrite c_{3}^{15}-c_{1}^{3} as \left(-c_{1}\right)^{3}+\left(c_{3}^{5}\right)^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).