Solve c-3-5-3c=-(-c+3)-(c-5)

$$c - 3 - 5 - 3 c = - ( - c + 3 ) - ( c - 5 )$$

Solve for c

$$c=-5$$

Steps for Solving Linear Equation

Subtract 5 from -3 to get -8.

$$c-8-3c=-\left(-c+3\right)-\left(c-5\right)$$

Combine c and -3c to get -2c.

$$-2c-8=-\left(-c+3\right)-\left(c-5\right)$$

To find the opposite of -c+3, find the opposite of each term.

$$-2c-8=-\left(-c\right)-3-\left(c-5\right)$$

To find the opposite of c-5, find the opposite of each term.

$$-2c-8=-\left(-c\right)-3-c-\left(-5\right)$$

The opposite of -5 is 5.

$$-2c-8=-\left(-c\right)-3-c+5$$

Add -3 and 5 to get 2.

$$-2c-8=-\left(-c\right)+2-c$$

Add -c to both sides.

$$-2c-8-c=2-c$$

Add c to both sides.

$$-2c-8-c+c=2$$

Combine -2c and c to get -c.

$$-c-8-c=2$$

Add 8 to both sides.

$$-c-c=2+8$$

Add 2 and 8 to get 10.

$$-c-c=10$$

Combine -c and -c to get -2c.

$$-2c=10$$

Divide both sides by -2.

$$c=\frac{10}{-2}$$

Divide 10 by -2 to get -5.

$$c=-5$$