Solve c*sqrt{(12-3)}*4=4/4+3/8

$$c \cdot \sqrt { ( 12 - 3 ) } \cdot 4 = \frac { 4 } { 4 } + \frac { 3 } { 8 }$$

Solve for c

$$c=\frac{11}{96}\approx 0.114583333$$

Steps for Solving Linear Equation

Subtract 3 from 12 to get 9.

$$4c\sqrt{9}=\frac{4}{4}+\frac{3}{8}$$

Calculate the square root of 9 and get 3.

$$4c\times 3=\frac{4}{4}+\frac{3}{8}$$

Multiply 4 and 3 to get 12.

$$12c=\frac{4}{4}+\frac{3}{8}$$

Divide 4 by 4 to get 1.

$$12c=1+\frac{3}{8}$$

Convert 1 to fraction \frac{8}{8}.

$$12c=\frac{8}{8}+\frac{3}{8}$$

Since \frac{8}{8} and \frac{3}{8} have the same denominator, add them by adding their numerators.

$$12c=\frac{8+3}{8}$$

Add 8 and 3 to get 11.

$$12c=\frac{11}{8}$$

Divide both sides by 12.

$$c=\frac{\frac{11}{8}}{12}$$

Express \frac{\frac{11}{8}}{12} as a single fraction.

$$c=\frac{11}{8\times 12}$$

Multiply 8 and 12 to get 96.

$$c=\frac{11}{96}$$