Solve c^2-3x-2=0

$$c ^ { 2 } - 3 x - 2 = 0$$

Solve for x

$$x=\frac{c^{2}-2}{3}$$

Steps for Solving Linear Equation

Subtract c^{2} from both sides. Anything subtracted from zero gives its negation.

$$-3x-2=-c^{2}$$

Add 2 to both sides.

$$-3x=-c^{2}+2$$

The equation is in standard form.

$$-3x=2-c^{2}$$

Divide both sides by -3.

$$\frac{-3x}{-3}=\frac{2-c^{2}}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$x=\frac{2-c^{2}}{-3}$$

Divide -c^{2}+2 by -3.

$$x=\frac{c^{2}-2}{3}$$

Solve for c (complex solution)

$$c=-\sqrt{3x+2}$$

$$c=\sqrt{3x+2}$$

Solve for c

$$c=\sqrt{3x+2}$$

$$c=-\sqrt{3x+2}\text{, }x\geq -\frac{2}{3}$$