Solve c^2-2x-1=0

$$c ^ { 2 } - 2 x - 1 = 0$$

Solve for x

$$x=\frac{c^{2}-1}{2}$$

Steps for Solving Linear Equation

Subtract c^{2} from both sides. Anything subtracted from zero gives its negation.

$$-2x-1=-c^{2}$$

Add 1 to both sides.

$$-2x=-c^{2}+1$$

The equation is in standard form.

$$-2x=1-c^{2}$$

Divide both sides by -2.

$$\frac{-2x}{-2}=\frac{1-c^{2}}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$x=\frac{1-c^{2}}{-2}$$

Divide -c^{2}+1 by -2.

$$x=\frac{c^{2}-1}{2}$$

Solve for c (complex solution)

$$c=-\sqrt{2x+1}$$

$$c=\sqrt{2x+1}$$

Solve for c

$$c=\sqrt{2x+1}$$

$$c=-\sqrt{2x+1}\text{, }x\geq -\frac{1}{2}$$