Solve c^2+6x+9=0

$$c ^ { 2 } + 6 x + 9 = 0$$

Solve for x

$$x=-\frac{c^{2}}{6}-\frac{3}{2}$$

Steps for Solving Linear Equation

Subtract c^{2} from both sides. Anything subtracted from zero gives its negation.

$$6x+9=-c^{2}$$

Subtract 9 from both sides.

$$6x=-c^{2}-9$$

Divide both sides by 6.

$$\frac{6x}{6}=\frac{-c^{2}-9}{6}$$

Dividing by 6 undoes the multiplication by 6.

$$x=\frac{-c^{2}-9}{6}$$

Divide -c^{2}-9 by 6.

$$x=-\frac{c^{2}}{6}-\frac{3}{2}$$

Solve for c (complex solution)

$$c=-\sqrt{-6x-9}$$

$$c=\sqrt{-6x-9}$$

Solve for c

$$c=\sqrt{-6x-9}$$

$$c=-\sqrt{-6x-9}\text{, }x\leq -\frac{3}{2}$$