Solve c^2+5c-24=

$$c ^ { 2 } + 5 c - 24 =$$

Factor

$$\left(c-3\right)\left(c+8\right)$$

Solution Steps

Factor the expression by grouping. First, the expression needs to be rewritten as c^{2}+ac+bc-24. To find a and b, set up a system to be solved.

$$a+b=5 ab=1\left(-24\right)=-24$$

Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -24.

$$-1,24 -2,12 -3,8 -4,6$$

Calculate the sum for each pair.

$$-1+24=23 -2+12=10 -3+8=5 -4+6=2$$

The solution is the pair that gives sum 5.

$$a=-3 b=8$$

Rewrite c^{2}+5c-24 as \left(c^{2}-3c\right)+\left(8c-24\right).

$$\left(c^{2}-3c\right)+\left(8c-24\right)$$

Factor out c in the first and 8 in the second group.

$$c\left(c-3\right)+8\left(c-3\right)$$

Factor out common term c-3 by using distributive property.

$$\left(c-3\right)\left(c+8\right)$$

Steps Using the Quadratic Formula

Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.

$$c^{2}+5c-24=0$$

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$c=\frac{-5±\sqrt{5^{2}-4\left(-24\right)}}{2}$$

Square 5.

$$c=\frac{-5±\sqrt{25-4\left(-24\right)}}{2}$$

Multiply -4 times -24.

$$c=\frac{-5±\sqrt{25+96}}{2}$$

Add 25 to 96.

$$c=\frac{-5±\sqrt{121}}{2}$$

Take the square root of 121.

$$c=\frac{-5±11}{2}$$

Now solve the equation c=\frac{-5±11}{2} when ± is plus. Add -5 to 11.

$$c=\frac{6}{2}$$

Divide 6 by 2.

$$c=3$$

Now solve the equation c=\frac{-5±11}{2} when ± is minus. Subtract 11 from -5.

$$c=-\frac{16}{2}$$

Divide -16 by 2.

$$c=-8$$

Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute 3 for x_{1} and -8 for x_{2}.

$$c^{2}+5c-24=\left(c-3\right)\left(c-\left(-8\right)\right)$$

Simplify all the expressions of the form p-\left(-q\right) to p+q.

$$c^{2}+5c-24=\left(c-3\right)\left(c+8\right)$$

Steps Using Direct Factoring Method

Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.

$$x ^ 2 +5x -24 = 0$$

Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C

$$r + s = -5 rs = -24$$

Two numbers r and s sum up to -5 exactly when the average of the two numbers is \frac{1}{2}*-5 = -\frac{5}{2}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>

$$r = -\frac{5}{2} - u s = -\frac{5}{2} + u$$

To solve for unknown quantity u, substitute these in the product equation rs = -24

$$(-\frac{5}{2} - u) (-\frac{5}{2} + u) = -24$$

Simplify by expanding (a -b) (a + b) = a^2 – b^2

$$\frac{25}{4} - u^2 = -24$$

Simplify the expression by subtracting \frac{25}{4} on both sides

$$-u^2 = -24-\frac{25}{4} = -\frac{121}{4}$$

Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u

$$u^2 = \frac{121}{4} u = \pm\sqrt{\frac{121}{4}} = \pm \frac{11}{2}$$

The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.

$$r =-\frac{5}{2} - \frac{11}{2} = -8 s = -\frac{5}{2} + \frac{11}{2} = 3$$

Evaluate

$$\left(c-3\right)\left(c+8\right)$$