Solve c^2+{-[2b-(3/3b-8/15b+4/1)]-(-b)}+3/5a^2-frac{17}{15}b

$$c ^ { 2 } + \{ - [ 2 b - ( \frac { 3 } { 3 } b - \frac { 8 } { 15 } b + \frac { 4 } { 1 } ) ] - ( - b ) \} + \frac { 3 } { 5 } a ^ { 2 } - \frac { 17 } { 15 } b$$

Evaluate

$$\frac{3a^{2}}{5}+c^{2}-\frac{5b}{3}+4$$

Solution Steps

Divide 3 by 3 to get 1.

$$c^{2}+-\left(2b-\left(1b-\frac{8}{15}b+\frac{4}{1}\right)\right)-\left(-b\right)+\frac{3}{5}a^{2}-\frac{17}{15}b$$

Combine 1b and -\frac{8}{15}b to get \frac{7}{15}b.

$$c^{2}+-\left(2b-\left(\frac{7}{15}b+\frac{4}{1}\right)\right)-\left(-b\right)+\frac{3}{5}a^{2}-\frac{17}{15}b$$

Anything divided by one gives itself.

$$c^{2}+-\left(2b-\left(\frac{7}{15}b+4\right)\right)-\left(-b\right)+\frac{3}{5}a^{2}-\frac{17}{15}b$$

To find the opposite of \frac{7}{15}b+4, find the opposite of each term.

$$c^{2}+-\left(2b-\frac{7}{15}b-4\right)-\left(-b\right)+\frac{3}{5}a^{2}-\frac{17}{15}b$$

Combine 2b and -\frac{7}{15}b to get \frac{23}{15}b.

$$c^{2}+-\left(\frac{23}{15}b-4\right)-\left(-b\right)+\frac{3}{5}a^{2}-\frac{17}{15}b$$

To find the opposite of \frac{23}{15}b-4, find the opposite of each term.

$$c^{2}+-\frac{23}{15}b+4-\left(-b\right)+\frac{3}{5}a^{2}-\frac{17}{15}b$$

Multiply -1 and -1 to get 1.

$$c^{2}-\frac{23}{15}b+4+b+\frac{3}{5}a^{2}-\frac{17}{15}b$$

Combine -\frac{23}{15}b and b to get -\frac{8}{15}b.

$$c^{2}-\frac{8}{15}b+4+\frac{3}{5}a^{2}-\frac{17}{15}b$$

Combine -\frac{8}{15}b and -\frac{17}{15}b to get -\frac{5}{3}b.

$$c^{2}-\frac{5}{3}b+4+\frac{3}{5}a^{2}$$

Expand

$$\frac{3a^{2}}{5}+c^{2}-\frac{5b}{3}+4$$

Solution Steps

Divide 3 by 3 to get 1.

$$c^{2}+-\left(2b-\left(1b-\frac{8}{15}b+\frac{4}{1}\right)\right)-\left(-b\right)+\frac{3}{5}a^{2}-\frac{17}{15}b$$

Combine 1b and -\frac{8}{15}b to get \frac{7}{15}b.

$$c^{2}+-\left(2b-\left(\frac{7}{15}b+\frac{4}{1}\right)\right)-\left(-b\right)+\frac{3}{5}a^{2}-\frac{17}{15}b$$

Anything divided by one gives itself.

$$c^{2}+-\left(2b-\left(\frac{7}{15}b+4\right)\right)-\left(-b\right)+\frac{3}{5}a^{2}-\frac{17}{15}b$$

To find the opposite of \frac{7}{15}b+4, find the opposite of each term.

$$c^{2}+-\left(2b-\frac{7}{15}b-4\right)-\left(-b\right)+\frac{3}{5}a^{2}-\frac{17}{15}b$$

Combine 2b and -\frac{7}{15}b to get \frac{23}{15}b.

$$c^{2}+-\left(\frac{23}{15}b-4\right)-\left(-b\right)+\frac{3}{5}a^{2}-\frac{17}{15}b$$

To find the opposite of \frac{23}{15}b-4, find the opposite of each term.

$$c^{2}+-\frac{23}{15}b+4-\left(-b\right)+\frac{3}{5}a^{2}-\frac{17}{15}b$$

Multiply -1 and -1 to get 1.

$$c^{2}-\frac{23}{15}b+4+b+\frac{3}{5}a^{2}-\frac{17}{15}b$$

Combine -\frac{23}{15}b and b to get -\frac{8}{15}b.

$$c^{2}-\frac{8}{15}b+4+\frac{3}{5}a^{2}-\frac{17}{15}b$$

Combine -\frac{8}{15}b and -\frac{17}{15}b to get -\frac{5}{3}b.

$$c^{2}-\frac{5}{3}b+4+\frac{3}{5}a^{2}$$