Solve c=4b+3c

$$c = 4 b + 3 c$$

Solve for b

$$b=-\frac{c}{2}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$4b+3c=c$$

Subtract 3c from both sides.

$$4b=c-3c$$

Combine c and -3c to get -2c.

$$4b=-2c$$

Divide both sides by 4.

$$\frac{4b}{4}=-\frac{2c}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$b=-\frac{2c}{4}$$

Divide -2c by 4.

$$b=-\frac{c}{2}$$

Solve for c

$$c=-2b$$

Steps for Solving Linear Equation

Subtract 3c from both sides.

$$c-3c=4b$$

Combine c and -3c to get -2c.

$$-2c=4b$$

Divide both sides by -2.

$$\frac{-2c}{-2}=\frac{4b}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$c=\frac{4b}{-2}$$

Divide 4b by -2.

$$c=-2b$$