Solve for a
a=2c-b
Solve for b
b=2c-a
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c=\frac{1}{2}a+\frac{1}{2}b
Divide each term of a+b by 2 to get \frac{1}{2}a+\frac{1}{2}b.
\frac{1}{2}a+\frac{1}{2}b=c
Swap sides so that all variable terms are on the left hand side.
\frac{1}{2}a=c-\frac{1}{2}b
Subtract \frac{1}{2}b from both sides.
\frac{1}{2}a=-\frac{b}{2}+c
The equation is in standard form.
\frac{\frac{1}{2}a}{\frac{1}{2}}=\frac{-\frac{b}{2}+c}{\frac{1}{2}}
Multiply both sides by 2.
a=\frac{-\frac{b}{2}+c}{\frac{1}{2}}
Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.
a=2c-b
Divide c-\frac{b}{2} by \frac{1}{2} by multiplying c-\frac{b}{2} by the reciprocal of \frac{1}{2}.
c=\frac{1}{2}a+\frac{1}{2}b
Divide each term of a+b by 2 to get \frac{1}{2}a+\frac{1}{2}b.
\frac{1}{2}a+\frac{1}{2}b=c
Swap sides so that all variable terms are on the left hand side.
\frac{1}{2}b=c-\frac{1}{2}a
Subtract \frac{1}{2}a from both sides.
\frac{1}{2}b=-\frac{a}{2}+c
The equation is in standard form.
\frac{\frac{1}{2}b}{\frac{1}{2}}=\frac{-\frac{a}{2}+c}{\frac{1}{2}}
Multiply both sides by 2.
b=\frac{-\frac{a}{2}+c}{\frac{1}{2}}
Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.
b=2c-a
Divide c-\frac{a}{2} by \frac{1}{2} by multiplying c-\frac{a}{2} by the reciprocal of \frac{1}{2}.
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