Solve c=4/3ab

$$c = \frac { 4 } { 3 } a b$$

Solve for a

$$\left\{\begin{matrix}a=\frac{3c}{4b}\text{, }&b\neq 0\\a\in \mathrm{R}\text{, }&c=0\text{ and }b=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$\frac{4}{3}ab=c$$

The equation is in standard form.

$$\frac{4b}{3}a=c$$

Divide both sides by \frac{4}{3}b.

$$\frac{3\times \frac{4b}{3}a}{4b}=\frac{3c}{4b}$$

Dividing by \frac{4}{3}b undoes the multiplication by \frac{4}{3}b.

$$a=\frac{3c}{4b}$$

Solve for b

$$\left\{\begin{matrix}b=\frac{3c}{4a}\text{, }&a\neq 0\\b\in \mathrm{R}\text{, }&c=0\text{ and }a=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$\frac{4}{3}ab=c$$

The equation is in standard form.

$$\frac{4a}{3}b=c$$

Divide both sides by \frac{4}{3}a.

$$\frac{3\times \frac{4a}{3}b}{4a}=\frac{3c}{4a}$$

Dividing by \frac{4}{3}a undoes the multiplication by \frac{4}{3}a.

$$b=\frac{3c}{4a}$$