Solve for c
c=-3y-7
Solve for y
y=\frac{-c-7}{3}
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c+7=-3y
Subtract 3y from both sides. Anything subtracted from zero gives its negation.
c=-3y-7
Subtract 7 from both sides.
3y+7=-c
Subtract c from both sides. Anything subtracted from zero gives its negation.
3y=-c-7
Subtract 7 from both sides.
\frac{3y}{3}=\frac{-c-7}{3}
Divide both sides by 3.
y=\frac{-c-7}{3}
Dividing by 3 undoes the multiplication by 3.
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Limits
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