Solve for c
c=\frac{k-6}{3}
Solve for k
k=3\left(c+2\right)
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3c+6=k
Multiply both sides of the equation by 3.
3c=k-6
Subtract 6 from both sides.
\frac{3c}{3}=\frac{k-6}{3}
Divide both sides by 3.
c=\frac{k-6}{3}
Dividing by 3 undoes the multiplication by 3.
c=\frac{k}{3}-2
Divide k-6 by 3.
3c+6=k
Multiply both sides of the equation by 3.
k=3c+6
Swap sides so that all variable terms are on the left hand side.
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