Solve for b
b=-3+\frac{4}{n}
n\neq 0
Solve for n
n=\frac{4}{b+3}
b\neq -3
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nb=4-3n
The equation is in standard form.
\frac{nb}{n}=\frac{4-3n}{n}
Divide both sides by n.
b=\frac{4-3n}{n}
Dividing by n undoes the multiplication by n.
b=-3+\frac{4}{n}
Divide 4-3n by n.
bn+3n=4
Add 3n to both sides.
\left(b+3\right)n=4
Combine all terms containing n.
\frac{\left(b+3\right)n}{b+3}=\frac{4}{b+3}
Divide both sides by b+3.
n=\frac{4}{b+3}
Dividing by b+3 undoes the multiplication by b+3.
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